5[h+2]=3[j-1]

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Solution for 5[h+2]=3[j-1] equation:


Simplifying
5[h + 2] = 3[j + -1]

Reorder the terms:
5[2 + h] = 3[j + -1]
[2 * 5 + h * 5] = 3[j + -1]
[10 + 5h] = 3[j + -1]

Reorder the terms:
10 + 5h = 3[-1 + j]
10 + 5h = [-1 * 3 + j * 3]
10 + 5h = [-3 + 3j]

Solving
10 + 5h = -3 + 3j

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 5h = -3 + -10 + 3j

Combine like terms: 10 + -10 = 0
0 + 5h = -3 + -10 + 3j
5h = -3 + -10 + 3j

Combine like terms: -3 + -10 = -13
5h = -13 + 3j

Divide each side by '5'.
h = -2.6 + 0.6j

Simplifying
h = -2.6 + 0.6j

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